# Line slope calculator 6x+7y=68

**Straight line given by points A[2; 8] and B[9; 2]**

## Calculation:

**Slope-intercept form of line:**y = -0.8571x+9.7143

**Canonical form of the line equation:**6x+7y-68 = 0

**Parametric form of the line equation:**

x = 7t+2

y = -6t+8 ; t ∈ R

**Slope:**m = -0.8571

**Slope angle of line: φ =**-40°36'5″ = -0.7086 rad

**X intercept:**x

_{0}= 11.3333

**Y intercept:**y

_{0}= q = 9.7143

**Distance line from the origin:**d

_{0}= 7.3756

**The length of the segment AB: |AB| =**9.2195

**Vector: AB =**(7; -6)

**Normal vector: n =**(6; 7)

**Midpoint of the segment AB: M =**[5.5; 5]

**Perpendicular Bisector equation:**7x-6y-8.5 = 0

**Vector OA = (2; 8) ; |OA| = 8.2462**

**Vector OB = (9; 2) ; |OB| = 9.2195**

**Scalar product OA .OB = 34**

**Angle ∠ AOB = 63°26'6″ = 1.1071 rad**